Physics: A 2.6 kg rock is dropped from a height of 10 m. With what speed will it strike the ground. Ignore air resistance. Solve using conservation of energy (start with Ebefore = Eafter).

Explanation:Momentum is given by . Let be the initial momentum of the object:If we doubled the mass, the new mass would be , and if we halved the velocity, the new velocity would be .Therefore, the final momentum would be:.....

A 2.6 kg rock is dropped from a height of 10 - id261014543654, junielouwho

Ответ:

matilda67

08.10.2021

Physics

$mgh = \frac{1}{2} m {v}^{2} \\ v = \sqrt{2gh} \\ = \sqrt{2 \times 9.8 \times 10} \: m. {s}^{ - 1}$

0,0(0 оценок)

Ответ:

wowihavefun

07.09.2022

Physics

$22.4\:\mathrm{kg\cdot m/s}$

Explanation:

Momentum is given by p=mv .

Let p_1 be the initial momentum of the object:

$p_1=m\cdot v=22.4$

If we doubled the mass, the new mass would be $2\cdot m$ , and if we halved the velocity, the new velocity would be $\frac{1}{2}\cdot v$ .

Therefore, the final momentum would be:

$p_f=2\cdot m\cdot \frac{1}{2}\cdot v=m\cdot v=\fbox{$22.4\:\mathrm{kg\cdot m/s}$}$ ..

0,0(0 оценок)

A 2.6 kg rock is dropped from a height of 10 m. With what speed will it strike the ground. Ignore air resistance. Solve using conservation of energy (start with Ebefore = Eafter).

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Physics

Ask an AI advisor a question