Rubendelarosa1529
06.09.2020 •
Physics
A 2-kg ball rolls down the hill. By the time it is at the bottom, the ball’s Kinetic Energy is 25 J. What is its velocity at the bottom of the hill?
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Ответ:
Explanation:
KE = ½ mv²
25 J = ½ (2 kg) v²
v = 5 m/s
Ответ:
19,200j
Explanation:
formular W=f×d
a) W=240N×20m
= 4,800j
b) W=200N×20m
=4000j
C) Td= 4800×4000\20×50
td= 19,200,000/1000
td= 19,200j
sorry if am wrong ☹️