A 2 kg RC car is driving at a speed of 4 m/s. The brakes are hit from the controller and the car slows down to a speed of 2 m/s. What is the work done by friction? *
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Ответ:
the work done by friction is 12 J.
Explanation:
Given;
mass of the car, m = 2 kg
initial speed of the car, u = 4 m/s
final speed of the car, v = 2 m/s
The work done by friction is equal to change in kinetic energy of the car,
W = ΔK.E
W = ¹/₂m(v² - u²)
W = ¹/₂ x 2 (2² - 4²)
W = -12 J (the negative sign indicates that it is a wasted energy)
Therefore, the work done by friction is 12 J.
Ответ:
If an object's average speed is 5 m/s, it will move 5 m in 1 s.
Explanation: