Physics: A 2100 kg truck is traveling east through an intersection at 2.0 m/s when it is hit simultaneously from the side and the rear. (Some people have all the luck!) One car is a 1200 kg compact traveling north at 5.0 m/s. The other is a 1500 kg midsize traveling east at 10 m/s. The three vehicles become entangled and slide as one body. What is their velocity (magnitude and direction) just after the collision?

Power is defined as the rate at which the work is accomplished. The correct answer is D. ...

A 2100 kg truck is traveling east through an intersection

Ответ:

richierichMBM7786

23.01.2022

Physics

speed is 3.41 meter per second and direction is 66.25 degrees

Explanation:

As per the conservation of momentum theory, Initial momentum is equal to final momentum

$Pi_{1200} + Pi_{1500} + Pi_{2100} = Pf_{1200} + Pf_{1500} + Pf_{2100} \\m_{1200} * v_{1200} + m_{1500} * v_{1500} + m_{2100} * v_{2100} = [ m_{1200} + m_{1500} + m_{2100}] * V_f$

Substituting the given values we get

Velocity in horizontal direction

$1200 * 5 + 0 + 2100 * 2 = 4800 * V_{fx}\\V_{fx} = 1.375 \frac{m}{s}$

Velocity in vertical direction

$1500*10 = 4800 * V_{fx}\\V_{fx} = 3.125 \frac{m}{s}$

Final velocity

$\sqrt{1.375 ^2 + 3.125^2}\\3.41=$

Direction of the velocity

$\alpha = tan^{-1} \frac{3.125}{1.375} \\= 66.25$

So speed is 3.41 meter per second and direction is 66.25 degrees

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