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lele142018
07.04.2020 •
Physics
A 3.6-volt battery is used to operate a cell phone for an hour. If the cell phone draws a current of 0.018 Amperes during that time, what is the energy lost by the battery?
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Ответ:
233.28Joules
Explanation:
Energy lost by the battery is expressed as
Energy = Power × Time
Since Power user up = Current (I)×potential difference (V)
Energy lost = current × potential difference × time
Energy used up = IVt
Given the following parameters
I = 0.018Amperes, V = 3.6Volts t = 1hour = 1×60×60 = 3600seconds
Energy lost. = 0.018×3.6×3600
Energy lost by the battery = 233.28Joules
Ответ:
No thank you and this should not be on this sit. This is inappropriate
Explanation: