Physics: A 300 g bird flying along at 6.2 m/s sees a 10 g insect heading straight toward it with a speed of 35 m/s (as measured by an observer on the ground, not by the bird). The bird opens its mouth wide and enjoys a nice lunch. Required: What is the bird s speed immediately after swallowing?

A 300 g bird flying along at 6.2 m/s sees a 10 g insect

rleiphart1

29.01.2022

The velocity of the bird is $v_f = 4.87 \ m/s$

Explanation:

From the question we are told that

The mass of the bird is $m_1 = 300 \ g = 0.3 \ kg$

The initial speed of the bird is $u_1 = 6.2 \ m/s$

The mass of the insect is $m_2 = 10 \ g = 0.01 \ kg$

The speed of the insect is $u_ 2 =-35 \ m/s$

The negative sign is because it is moving in opposite direction to the bird

According to the principle of linear momentum conservation

m_1 u_1 + m_2 u_2 = (m_1 + m_2 )v_f

substituting values

(0.3 * 6.2 ) + (0.01 * (-35)) = (0.3 + 0.01 )v_f

1.51 = 0.31 v_f

$v_f = 4.87 \ m/s$

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