Physics: A 45.0kg mass is at the top of an incline that has a vertical height of 16m. As the box slides to the bottom it loses 2630 J of energy through friction. How fast is it moving at the bottom?

A 45.0kg mass is at the top of an incline that has

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11.08.2020

Acceleration = 6m/s²

Explanation:

Given the following data;

Initial velocity = 35m/s

Final velocity = 65m/s

Time = 5 seconds

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Where,

a is acceleration measured in $ms^{-2}$ v and u is final and initial velocity respectively, measured in $ms^{-1}$ t is time measured in seconds.

Substituting into the equation, we have

$a = \frac{65 - 35}{5}$

$a = \frac{30}{5}$

Acceleration = 6m/s²

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