Physics: A 7.13 kg bowling ball moves at 4.14 m/s. How fast must a 2.34 g Ping-Pong ball move so that the two balls have the same kinetic energy? Answer in units of m/s.

The answer i got on my test is C= C is speeding up and D is moving at a constant velocity...

A 7.13 kg bowling ball moves at 4.14 m/s. How fast

Ответ:

colemanjosiah03

20.01.2022

Physics

243.43 m/s

Explanation:

Hello,I can help you with this.

the kinetic energy is asociated to the mass and the speed of an object,and it is given by:

$E_{k}=\frac{1}{2}mv^{2}$

where:

$E_{k}$ is the kinetic energy

m is the mass of the object

v is the speed of the object

Step 1

let

bowling ball =mass1=7.13 kg

Speed(1)=4.14 m/s

Ping-Pong ball

mass2=2.34 g

it is given in grams so we have to convert into Kg (dividing by 1000,1kg=1000 g)

$2.34g(\frac{1kg}{1000g} )=0.00234kg$

so, mass2=0.00234kg

Step 2

according to the problem both have equal Kinetic energy

$E_{1}=\frac{1}{2}m_{1} v_{1} ^{2}\\E_{2}=\frac{1}{2}m_{2} v_{2} ^{2}\\\frac{1}{2}m_{1} v_{1} ^{2}=\frac{1}{2}m_{2} v_{2} ^{2}\\isolate\ v_{2} \\m_{1} v_{1} ^{2}=m_{2} v_{2} ^{2}\\\frac{m_{1} v_{1} ^{2}}{m_{2}}=v_{2} ^{2} \\v_{2}=\sqrt{\frac{m_{1} v_{1} ^{2}}{m_{2}}}\\v_{2}=\sqrt{\frac{7.13kg*(4.41\frac{m}{s}) ^{2}}{0.00234kg}} \\\\v_{2}=\sqrt{59258.526\frac{m^{2} }{s^{2} } } \\\\\\v_{2}=243.43 m/s$

so the speed of the ping-pong ball should be 243.43 m/s

Have a good day.

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A 7.13 kg bowling ball moves at 4.14 m/s. How fast must a 2.34 g Ping-Pong ball move so that the two balls have the same kinetic energy? Answer in units of m/s.

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