A 7.7cm length of straight wire run horizontally along a north south line . The wire carries a 3.45 current flowing northward through a uniform 1.25 T magnetic field vertical upward. Find the magnetude and directions of the force wire

F = 0.332 N in the east direction

Explanation:

Length, L = 7.7 cm = 7.7 * 0.01 = 0.077 m(along the north south)

Current, I = 3.45 A (northwards)

Magnetic field, B = 1.25 T (vertically upwards)

The magnitude of the force is given by, F = ILBsin90

F = 3.45 * 0.077 * 1.25 * 1

F = 0.332 N

The direction of the force is calculated using the Right Hand Thumb Rule:

It states that "Hold the wire carrying current in your right hand so that the thumb points along the wire in the direction of the current, then the fingers will encircle the wire in the direction of the lines of magnetic force."

Based on the Right Hand Thumb Rule, the magnetic force will act in the east direction

h(x-1)=4x-7

Step-by-step explanation:

Given :

h(x)=4x-3

Now,

putting the value of x =x-1

h(x-1)=(4(x-1)-3)

h(x-1)=4x-4-3

h(x-1)=4x-7

Answer will be h(x-1)=4x-7