A 75 kg baseball player runs at a velocity of 6 m/s and sliding 2 m what is the force of friction that acts upon him?
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Ответ:
1350N
Explanation:
Given data
mass= 75kg
velocity= 6m/s
distance= 2m
The expression for the applied force is given as
F= mv^2/d
Substitute
F= 75*(6)^2/ 2
F= 75*36/2
F= 2700/2
F= 1350N
Hence the force is 1350N
Ответ:
Explanation:
Difference in the measurement by shuttle crew Δ d = 238857 - 226316 miles
= 12541 miles
Actual measurement = 238857 miles
percentage error
= (12541 / 238857 ) x 100
= 5.25 %