A 75kg passenger at the bottom of a roller coaster loop that has a radius of 20m. If the roller coaster car is moving 10m/s, what is the apparent weight of the passenger? g

The apparent weight of the passenger is 360 N

Explanation:

Given;

The mass of the passenger, m = 75 kg

radius of the loop, r = 20 m

velocity of the roller coaster, v = 10 m/s

Centripetal force acting on this passenger is given as;

where;

F is the centripetal force acting on the passenger

m is the mass of the passenger

v is the velocity of the passenger

r is the radius of the track

Real weight of the passenger,

W = mg

where;

g is acceleration due to gravity

W = 75 x 9.8

W = 735 N

Apparent weight of the passenger = Real weight - Centripetal force

Apparent weight of the passenger  = 735 N - 375 N

Apparent weight of the passenger = 360 N

Therefore, the apparent weight of the passenger is 360 N

the impulse must be the same in these two cases    F t = m ()

Explanation:

For this exercise we use the relationship between momentum and momentum

         I = Δp

         F t = m v_f - m v₀

To know the speed we use the conservation of energy

starting point. Highest point

       Em₀ = U = m g h

fincla point. Just before the crash

      Em_f = K = ½ m v²

energy is conserved

        Em₀ = Em_f

        m g h = ½ m v²

         v =

we substitute in the impulse relation

     F t = m ()

therefore we can see that as in case the initial and final heights are equal, the impulse must be the same in these two cases