domenicaBeBe2007
10.10.2021 •
Physics
A ball is thrown vertically down from the edge of a cliff with a speed of 7 m/s, how high is the cliff, if it took 22 s for the ball to reach the ground?
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Ответ:
Distance = speed × time
Speed= 7m/s
Time= 22s
Distance= 7×22
Distance=154m
Therefore, the cliff is 154m high.
Ответ:
i think the answer is C i dunno hope this helps ^^
Explanation: