Disd112984
15.02.2020 •
Physics
A bar of steel has the minimum properties Se = 40 kpsi, Sy = 60 kpsi, and Sut = 80 kpsi. The bar is subjected to steady torsional stress (τm) of 15.3 kpsi, alternating torsional stress (τa) of 10 kpsi, and alternating bending stress (σa) of 12.4 kpsi. Find the factor of safety guarding against a static failure, and either the factor of safety guarding against a fatigue failure or the expected life of the part.
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Ответ:
The safety factor against the static failure as per Von Mises criteria is 2.05 whereas The factor of safety guarding the fatigue failure as per modified Goodman Criteria is 1.56.
Explanation:
For the bar as Von Mises criteria is given as
Here
is the bending stress given as 12.4 kpsi
T is the torsional stress which is given as 15.3 kpsi
So the safety factor against static failure is given as
The safety factor against the static failure as per Von Mises criteria is 2.05.
For fatigue failure,as per Modified Goodman criteria
Here
The factor of safety guarding the fatigue failure as per modified Goodman Criteria is 1.56
Ответ:
B IS YOUR ANSWER.
Soft sound has small amplitude and louder sound has large amplitude. Since, the second wave has large amplitude, it will have the loudest sound.