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aambitiouss
06.05.2020 •
Physics
A beaker of water rests on an electronic balance that reads 875.0 g. A 2.75-cm-diameter solid copper ball attached to a string is submerged in the water, but does not touch the bottom. What are the tension in the string and? a. Find the tension in the string. (10pts) b. What is the new balance reading? (10pts)A beaker of water rests on an electronic balance that reads 875.0 g. A 2.75-cm-diameter solid copper ball attached to a string is submerged in the water, but does not touch the bottom. What are the tension in the string and? a. Find the tension in the string. (10pts) b. What is the new balance reading? (10pts)
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Ответ:
a
The tension in the string is![T = 0.85 N](/tpl/images/0645/9531/3bbfe.png)
b
The new balance reading is![M_b = 885.86 g](/tpl/images/0645/9531/8e187.png)
Explanation:
From the question we are told that
The mass of the beaker of water is![m = 875 .0g](/tpl/images/0645/9531/53534.png)
The diameter of the copper ball is![d = 2.75 cm = \frac{2.75}{100} = 0.0275 m](/tpl/images/0645/9531/1ca74.png)
There are two forces acting on the copper ball
The first is the Buoyant force of the water pushing it up which is mathematically represented as
Where
is the density of water which has value of ![\rho = 1000 kg/m^3](/tpl/images/0645/9531/d88a0.png)
g is the acceleration due to gravity![g= 9.8 \ m/s^2](/tpl/images/0645/9531/52400.png)
The radius r is![r = \frac{d}{3} = \frac{0.0275}{2} = 0.01375 m](/tpl/images/0645/9531/c5c87.png)
Substituting value
Substituting for F
The second force is the weight of the copper ball which is mathematically represented as
Now m is the mass which can be mathematically evaluated as
Where is the density of copper with value of![\rho_c = 8960 kg /m^3](/tpl/images/0645/9531/12542.png)
So![m = 8960 * 1.089 *10^{-5}](/tpl/images/0645/9531/cc0d0.png)
So the weight of copper is
Now the tension the string would be mathematically evaluated as
So![T = 0.956 - 0.1067](/tpl/images/0645/9531/ce373.png)
From this value we that the string is holding only 0.85 N of the copper weight thus (0.956 - 0.85 = 0.1065 N ) is being held by the balance
Now the mass equivalent of this weight is mathematically evaluated as
Converting to grams
So the new balance reading is
Ответ:
it is 3 my dude
Explanation:
sir and over the crown STOP RESICTING