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titofigueroa777
21.06.2020 •
Physics
A body has an initial velocity of 12 m s^-1 and is brought to rest over a distance of 45 m. What is the acceleration of the body?
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Ответ:
-1.46 m/s^2
Explanation:
Write down what is given first:
v0 = 12 m/s
vf = 0 m/s
d = 45 m
We are trying to find acceleration, so we will use the equation vf^2 = v0^2 + 2ad
Plug in the values we have:
0^2 = 12^2 + (2 x 45 x a)
a = - 1.46 m/s^2
Note that this acceleration is negative because the body is slowing down, so the acceleration with be negative, because the change in velocity is negative.
Ответ:
Hey,
We can dilute the solution with H2O