A cable with a linear density of \mu=0.109~\text{kg/m}μ=0.109 kg/m is hung from telephone poles. The tension in the cable is 572 N. The distance between poles is 19.9 meters. The wind blows across the line, causing the cable resonate. A standing waves pattern is produced that has 4.5 wavelengths between the two poles. Assuming room temperature air, what is the frequency of the hum?
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Ответ:
Explanation:
The equation of the speed of a mechanical wave in terms of the tension and linear density, of the cable in our case, is given by:
Where:
T is the tension of the cable (T = 572 N)μ is the linear density of the cable (μ = 0.109 kg/m)And we know that v = λ*f
λ is the wavelengthf is the frequencyBecause a standing waves pattern is produced that has 4.5 wavelengths between the two poles and the distance between poles is 19.9 meters, the value of the wavelength is: λ = 19.9/4.5 = 4.4 m.
Therefore, the frequency will be:
I hope it helps you!
Ответ:
The power of this student is probably climbing power or flying power.
I hope this is correct, have a great day!