(a) calculate the magnitude of the gravitational force exerted on a 1,320-kg satellite that is a distance of two earth radii from the center of the earth. n
(b) what is the magnitude of the gravitational force exerted on the earth by the satellite? n
(c) determine the magnitude of the satellite's acceleration. m/s2
(d) what is the magnitude of the earth's acceleration? m/s2 additional materials

(a) 3224.27 N

(b) 3224.27 N

(c) 2.443 m/s^2

(d) 5.37 x 10^-22 m/s^2

Explanation:

Mass of satellite, m = 1320 kg

mas of earth, M = 6 x 10^24 kg

Radius of earth, r = 6.4 x 10^6 m

(a) The force of gravitation between the earth and the satellite is given by

where, d is the distance between the two objects

F = 3224.27 N

(b) The force on earth is same as the force on satellite.

F = 3224.27 N

(c) Acceleration of satellite = Force on satellite / mass of satellite

Acceleration of satellite = 3224.27 / 1320 = 2.443 m/s^2

(d) Acceleration of earth = Force on earth / mass of earth

Acceleration of satellite = 3224.27 / (6 x 10^24) = 5.37 x 10^-22 m/s^2

omg i lo ve the point s id k the ans wer but ill try to help

Explanation:

it is based on newtons 3rd law for every action there is an equal and opposite reaction

as the water comes out of  the sprinkler an equal and opposites force comes in to play hence the sprinkler starts rotating