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chrissulli4605
27.12.2020 •
Physics
A car accidentally rolls of cliff as it leaves the cliff it has a horizontal velocity of 15 m/s,it hits the ground 60m from the shore line calculate the height of the cliff
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Ответ:
The height of the cliff is 78.4 m
Explanation:
Horizontal Launch Motion
When an object is thrown horizontally with a speed v from a height h, it describes a curved path exclusively ruled by gravity until it hits the ground.
The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
Where g is the acceleration of gravity.
The maximum horizontal distance traveled by the object can be calculated as follows:
If the horizontal distance and the speed are known, we can solve the equation above for h:
The car leaves a cliff at a horizontal speed of v=15 m/s and hits the ground d=60 m from the shoreline. Thus the height of the cliff is:
Calculating:
h = 78.4 m
The height of the cliff is 78.4 m
Ответ:
Explanation:
Data given
temperature =700c
Density=10.35g/cm^3
but
Nv is the number of vacant site and N is the number of lattice site.
Since the number of lattice site can also b computed as
if we substitute the value of the number of lattice into the first equation, we arrive at