A car starts from rest and travels with a uniform acceleration to a final velocity of 20m/s in 4seconds and it maintains this velocity for 5seconds and decelerates uniformly to rest.
I. Sketch the velocity time graph
II.Calculate the total distance covered
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Ответ:
The car travels the distance of 225m before coming to rest.
Explanation:
Here,
v = 45m/s
t = 5s
d = v × t
Therefore,
d = 45 × 5
= 225m