A car weighing 16,170 newtons is placed on a hydraulic lift. Piston B has an area of 5,005 cm? and piston A has an area of 65 cm². What force must be exerted on piston A to lift the car?

P = F/A where Pequals pressure, Fequals force, and A equals area

210N

Explanation:

According to pascal principle

Fb/Ab = Fa/Aa

Given

Fb = 16,170N

Ab = 5,005cm²

Fa = ?

Aa = 65 cm².

Fa is the force that must be exerted on piston A to lift the car

Substitute

16170/5005 = Fa/65

Cross multiply

5005Fa = 65 * 16170

5005Fa = 1,051,050

Fa = 1,051,050/5005

Fa = 210N

Hence the required force is 210N

p = 6.64 cm

Explanation:

For this exercise we use the equation of the constructor

where f is the focal length, p and q are the distance to the object and the image, respectively

They tell us the focal length f = 2.2 cm and that the image as far as it can go is q = 3.29 cm, let's find the position of the object that creates this image

          1 / p = 1 / 2.2 - 1/3.29

           1 / p = 0.15059

           p = 6.64 cm

therefore the farthest distance from the object is 6.64 c