A chair is pushed forward with a force of 185 N. The gravitational force of earth on the chair is 155 N downward. The force of friction acting on the chair is 55 N. Draw a free-body diagram showing all forces acting on the chair. Determine the magnitude of any missing force values AND determine the net force acting on the chair.

For all the forces applied on any object, their net sum is called Net force applied on the object. So, the net force on the chair is 135 N.

The attachment shows the diagram of the chair with all forces.

Given forces on the chair are 185 N in forward direction, 155 N in downward direction that is the gravitation force of the Earth and Friction force in backward direction is 55 N.

In balance condition of the chair, gravitation force of the earth acts on the chair which is equal and opposite in directions. Hence the net force on the chair is the sum of all the forces applicable on the chair.

Net Force = Force in Forward Direction + Friction Force + Gravitation Force in Downward Direction + Gravitational Force in Upward Direction.

Net Force = 185 N +55 N + 155 N -155 N

Net Force = 135 N.

Hence the Net Force on the Chair is 135 N.

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The net force on the chair is 100N

Explanation:

The free body diagram is attached below.

According to the condition,

when a downward gravitational force of 155N of earth acts then an equal opposite upward force of same magnitude also acts on the chair.

Therefore, the normal force acting on the chair is 155N

When a chair is pushed forward on a surface, then a frictional force also acts on it in opposite direction.

The net force acting on the chair is = F - f

Where,

F is the applied force

f is the force of friction

Net force = 155N - 55N

Fnet = 100N

Therefore, net force on the chair is 100N

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Explanation: