A charged particle moving through a magnetic field at right angles to the field with a speed of 24.7 m/s experiences a magnetic force of 2.38 10-4 N. Determine the magnetic force on an identical particle when it travels through the same magnetic field with a speed of 5.64 m/s at an angle of 21.2° relative to the magnetic field. N
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Ответ:
Explanation:
let the charge is q. velocity, v = 24.7 m/s
magnetic force, F = 2.38 x 10^-4 N
Let the magnetic field is B.
Velocity, v' = 5.64 m/s
angle, θ = 21.2°
The force experienced by a charged particle placed in a magnetic field is given by
F = q x v x B x Sinθ
in first case
2.38 x 10^-4 = q x 24.7 x B x Sin 90 .... (1)
in second case
F = q x 5.64 x B x Sin 21.2° .... (2)
Divide equation (2) by equation (1), we get
F = 1.97 x 10^-5 N
Ответ: