A current carrying gold wire has diameter 0.84 mm. The electric field in the wire is 0.49 V/m. What are (a) the current carried by the wire; (b) the potential difference between two points in the wire 6.4 m apart; (c) the resistance of a 6.4-m length of this wire

Explanation:

Given that,

Diameter of the gold wire, d = 0.84 mm

Radius, r = 0.42 mm

Electric field in the wire, E = 0.49 V/m

(a) Electric current density is given by :

And electric field is :

is resistivity of Gold wire

So,

(b) The potential difference between two points in the wire is given by :

(c) Resistance of a wire is given by :

Hence, this is the required solution.

As it stands now, that statement is false.

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