Physics: A current of 7.79 A in a solenoid of length 10.6 cm creates a 0.201 T magnetic field at the center of the solenoid. How many turns does this solenoid contain? turns :

ms = 0.3 so p = 0.3 Therefore, 0.3 is X,...

A current of 7.79 A in a solenoid of length 10.6

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20.01.2022

Therefore,

2178 number of turns are there in Solenoid.

Explanation:

Given:

Current, I = 7.79 A

Length of Solenoid,

$L =10.6\ cm=\dfrac{10.6}{100}=0.106\ meter$

magnetic field at the center of the solenoid,

B = 0.201 Tesla

To Find:

N = ? turns

Solution:

Magnetic field at the center of the solenoid is given as,

$B=\dfrac{\mu_{0}\times N\times I}{L}$

Where,

B = Magnetic Field,

N = Number of turns,

I = Current,

L = Length of Solenoid

$\mu_{0}=permeability\ of\ free\ space=4\pi\times 10^{-7}\ H/m$

Substituting the values we get

$N=\dfrac{B\times L}{\mu_{0}\times I}$

$N=\dgrac{0.201\times 0.106}{4\pi\times 10^{-7}\times 7.79}=2177.58$

$N\approx 2178\ turns$

Therefore,

2178 number of turns are there in Solenoid.

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