A discus thrower turns with angular acceleration of 50 rad/s2, moving the discus in a circle of radius 0.80m. Find the radial and tangential components of acceleration of the discus when the angular velocity is 10 rad/s. (80 m/s2, 40 m/s2).
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Ответ:
The value of tangential acceleration
40 ![\frac{m}{s^{2} }](/tpl/images/0562/8402/28f2b.png)
The value of radial acceleration![\alpha_{r} = 80 \frac{m}{s^{2} }](/tpl/images/0562/8402/010e7.png)
Explanation:
Angular acceleration = 50![\frac{rad}{s^{2} }](/tpl/images/0562/8402/21fb2.png)
Radius of the disk = 0.8 m
Angular velocity = 10![\frac{rad}{s}](/tpl/images/0562/8402/13561.png)
We know that tangential acceleration is given by the formula![\alpha_{t} =](/tpl/images/0562/8402/a0bf1.png)
![r \alpha](/tpl/images/0562/8402/4dfb8.png)
Where r = radius of the disk
⇒
0.8 × 50
⇒
40 ![\frac{m}{s^{2} }](/tpl/images/0562/8402/28f2b.png)
This is the value of tangential acceleration.
Radial acceleration is given by
Where V = velocity of the disk = r![\omega](/tpl/images/0562/8402/a8223.png)
⇒ V = 0.8 × 10
⇒ V = 8![\frac{m}{s}](/tpl/images/0562/8402/406de.png)
Radial acceleration
This is the value of radial acceleration.
Ответ:
A,C,E
Explanation:
I shows correct