abigail018
17.07.2020 •
Physics
A diver running at 2.5 m/s dives out horizontally from the edge of a vertical cliff and 3.0 seconds later reaches the water below. How far from its base did the diver hit the water
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Ответ:
Explanation:
u = 2.5 m/s
v = 0
t = 3sec
s = ?
s = (u+v)/t
s = (0+2.5)/3
s = 2.5/3 = 0.83 m
Ответ:
an upward buoyant force and a downward force of gravity.