A force of 90.0 newtons is applied to a cart traveling at 15.0 meters per second. After the force has been applied for 2.00 seconds, it comes to rest. What is the magnitude
of the impulse applied to the cart over these 2.00 seconds?

180Ns

Explanation:

Given parameters:

Force applied  = 90N

Velocity  = 15m/s

Time taken  = 2s

Unknown:

Impulse applied to the cart  = ?

Solution:

The impulse is effect of force acting on a body through time.

 It is mathematically expressed as;

 Impulse  = Force x time

 So;

 Impulse on the car  = 90 x 2  = 180Ns

a=-1.58 m/s^2

Explanation:

Vo=34m/s

Vf=15m/s

t=12s

a= dV/dt = (Vf-Vo) /t = (15-34)/12

= - 19/12 = - 1.58m/s2