tricklts15
07.02.2021 •
Physics
A gas has an initial volume of 24.6 L at a pressure of 1.90 atm and a temperature of 335 K. The pressure of the gas increases to 3.50 atm, and the volume of the gas increases to 31.3 L. What is the final temperature of the gas? 143 K 231 K 485 K 785 K
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Ответ:
the final temperature of the gas is 785.18 K
Explanation:
The computation of the final temperature of the gas is shown below:
Here we apply the gas law
= PV ÷ T
Given that
P1 = 1.9 atm
V1 = 24.6 L
T1 = 335 K
P2 = 3.5 atm
V2 = 31.3 L
T2 = ?
Now
P1V1 ÷ T1 = P2V2 ÷ T2
(1.9 × 24.6) ÷ 335 = (3.5 × 31.3)/T2
T2 = 785.18 K
hence, the final temperature of the gas is 785.18 K
Ответ:
it's possible to calculate an object's velocity at any moment along its path. This is called instantaneous velocity and it is defined by the equation v = (ds)/(dt),in other words, the derivative of the object's average velocity equation.