Physics: A high power line carries a current of 1.0 kA. What is the strength of the magnetic field this line produces at the ground, 10 m away? ( μ 0 = 4π × 10 -7 T ∙ m/A)

sorry, thanks for 50 point, report all u want cheaterExplanation:...

A high power line carries a current of 1.0 kA. What

drzewostan5716

21.01.2022

The strength of the magnetic field that the line produces is $2x10^{-5} Tesla$ .

Explanation:

From Biot-Savart law, the equation to determine the strength of the magnetic field for any straight wire can be deduced:

$B = \frac{\mu_{0}I}{2\pi r}$ (1)

Where $\mu_{0}$ is the permiability constant, I is the current and r is the distance from the wire.

Notice that it is necessary to express the current, I, from kiloampere to ampere.

$I = 1.0kA \cdot \frac{1000A}{1kA}$ ⇒ 1000A

Finally, equation 1 can be used:

$B = \frac{(4\pi x10^{-7}T.m/A)(1000A)}{2\pi (10m)}$

$B = 2x10^{-5}T$

Hence, the strength of the magnetic field that the line produces is $2x10^{-5} Tesla$ .

0,0(0 оценок)