A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of +41.0 m/s. (a) If the goalie catches the puck with his glove in a time of 2.33 x 10-3 s, what is the magnitude of the average force exerted on the goalie by the puck?

2991.42 N

Explanation:

For this problem, we'll use the equations: momentum= mass x velocity and impulse = change in momentum, and impulse=force x time.

initial momentum; p1 = 0.17 x 41 = 6.97 kg.m/s

final momentum; p2 = 0, because final velocity is 0 m/s

Thus,

impulse = p1 - p2= 6.97 - 0 = 6.97 kg.m/s

Finally, impulse= Force x time,

Thus, Force = Impulse/time

Force= 6.97/ (2.33 x 10^(-3)) = 2991.42 N

V = 3.0 x 10⁸ m/s         (This is the same for all types of electromagnetic waves)

f = 88.6 MHz = 8.86 x 10⁷ Hz

λ = ?

V = fλ

λ = V/f = (3 x 10⁸)/(8.86 x 10⁷)

  =  3.4 m     [Ans]

Hope this helps!