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maltipoosarecool
25.05.2020 •
Physics
A hollow cylindrical (inner radius = 1.0 mm, outer radius = 3.0 mm) conductor carries a current of 80 A parallel to its axis. This current is uniformly distributed over a cross section of the conductor. Determine the magnitude of the magnetic field at a point that is 2.0 mm from the axis of the conductor.
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Ответ:
The magnetic field is![B = 3 mT](/tpl/images/0665/1574/bae5b.png)
Explanation:
From the question we are told that
The inner radius is![r_i = 1.00 mm =1*10^{-3} \ m](/tpl/images/0665/1574/9165e.png)
The outer radius is![r_2 = 3.00 \ mm = 3.0 *10^{-3} \ m](/tpl/images/0665/1574/a5e2a.png)
The distance from the axis of the conductor is![d =2.0 \ mm = 2.0 *10^{-3} \ m](/tpl/images/0665/1574/a3b8e.png)
The current carried by the conductor is![I = 80 A](/tpl/images/0665/1574/5e5e7.png)
According to Ampere's circuital law , the magnetic field at a point that is
from the axis of the conductor
Where
is the permeability of free space with a value of ![\mu_o = 4 \pi *10^{-7} N/A^2](/tpl/images/0665/1574/ce383.png)
substituting values
Ответ:
belts around 60° north and 60° south latitude. Convection cells are caused by this rising and sinking of air.