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mucciak3634
04.12.2019 •
Physics
:a laser beam is incident on two slits with separation d-0.038 mm. a screen is placed l-1.6 m from the slits. the wavelength of the laser light is a 4750 å. and θ2 are the angles to the first and second bright fringes above the center of the screen. otheex ee 25% part (a) express sin(91) in terms of d and λ. sin(θ 1) add v correct! 25% part (b) express sin(92) in terms of d and λ. sin(02) (2 a )yd correct 25% part (c) express the distance between the two bright fringes on the screen, y, in terms of θ1, θ2 and l. grade s deductic potentia 9 cotan(0) cotan(02) in(a)n 4 5 6 cos(0) | (.ilm-17 8 cos(α) cos(φ) submiss attempts per detailed sin(φ) tan(6) sin(0) tan(01) hint i give up! submit feedback: deduction per feedback hints: 0%, deduction per hint. hints remaining: 2 25% part (d) solve for the numerical value of y ¡n meters.
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Ответ:
Explanation:
Distance between two slits d = .038 x 10⁻³m
Distance of screen L = 1.6 m
Wave-length of light λ = 4750 x 10⁻¹⁰ m
If x₁ be the position of first bright fringe on the screen
Sinθ₁ = x₁ / L
For position of second bright fringe
Sinθ₂ = x₂ / L
Again, for the formation of first bright fringe
a ) path difference = λ
x₁ d / L = λ
d Sinθ₁ = λ
Sinθ₁ = λ / d
b ) Similarly for second bright fringe
Sinθ₂ = 2 λ / d
c ) Distance between two bright fringes
x₂ - x₁ = y
y = L ( Sinθ₂ - Sinθ₁ )
d )
y = L ( Sinθ₂ - Sinθ₁ )
= L ( 2 λ / d - λ / d )
= Lλ / d
=![\frac{1.6\times4750\times10^{-10}}{.038\times10^{-3}}](/tpl/images/0402/5967/055f7.png)
= 2 x 10⁻² m
= 2 cm .
Ответ:
given that
mass of ball = 0.095 kg
initial velocity of ball towards the wall = 40 m/s
final velocity of the ball after it rebound = 30 m/s
now change in momentum is given as
So change in momentum will be 6.65 kg m/s