A light ray propagates in Material 1 with index of refraction n 1 = 1.23 n1=1.23 , strikes an interface, then passes into Material 2 with index of refraction n 2 = 1.31 n2=1.31 . The angle of incidence at the interface is θ 1 = 24.5 θ1=24.5 °. Find the angle of refraction θ 2 θ2 .

22.916136degrees.

Explanation:

Snell's Law relates the refractive indices of two materials and their incidence and reflected angles in following way.

Where left side is for incidence ray and the material that it is in and the right side is for refracted ray and its material .

given that

  and  substituting these in Snell's law formula and solving for unknown gives, degrees, which is our refracted angle.

Its A because its both