A man weighing 700 NN and a woman weighing 440 NN have the same momentum. What is the ratio of the man's kinetic energy KmKmK_m to that of the woman K
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Ответ:
The ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.
Explanation:
Given;
weight of the man, W = 700 N
Weight of the woman, W = 440 N
momentum is given by;
Kinetic energy of the man;
Momentum of the man is calculated as;
The kinetic energy of the woman is given by;
The momentum of the woman is given;
Since, momentum of the man = momentum of the woman
mass of the mas = 700 / 9.8 = 71.429
mass of the woman is = 440 / 9.8 = 44.898
Therefore, the ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.
Ответ: