a marble rolls off a table with a speed of 2.30 m/s. if the table is 1.12 m high, how far from the
base of the table does the marble land? (find the time in the air first.)
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Ответ:
1.10 m
Explanation:
First, find the time it takes to land.
Given, in the y direction:
Δy = 1.12 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
(1.12 m) = (0 m/s) t + ½ (9.8 m/s²) t²
t = 0.478 s
Next, find the distance traveled in that time.
Given, in the x direction:
v₀ = 2.30 m/s
a = 0 m/s²
t = 0.478 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (2.30 m/s) (0.478 s) + ½ (0 m/s²) (0.478 s)²
Δx = 1.10 m
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