A mass m is located at the origin; a second mass m is at x = d. A third mass m is above the first two so the three masses form an equilateral triangle. What is the net gravitational force on the third mass?
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Ответ:
Explanation:
For equilateral triangle,
Force between masses,
Therefore,
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Ответ:
√3 * Gm²/d²
Explanation:
m1 = m, m2= m, distance = d. hence:
F = Gm²/d²
Let the origin be A, the point x = d be B and the point above the first two is C.
The net force acting on the third mass (point C)
= ![F_A+F_B](/tpl/images/1008/9212/1a4e3.png)
Let j represent the vertical component and i the horizontal component. Hence:
Ответ: