Physics: A(n) 6 kg object moving with a speed of 8.6 m/s collides with a(n) 17 kg object moving with a velocity of 11 m/s in a direction 20◦ from the initial direction of motion of the 6 kg object. 8.6 m/s 11 m/s 17 kg 6 kg 20◦ What is the speed of the two objects after the collision if they remain stuck together? Answer in units of m/s.

Double the pressure, half the volume....

A(n) 6 kg object moving with a speed of 8.6 m/s

cxttiemsp021

19.01.2022

The speed of the two objects after the collision if they remain stuck together is 10.26 m/s.

Explanation:

Given that,

Mass of object = 6 kg

Speed of object = 8.6 m/s

Other object = 17 kg

Velocity = 11 m/s

Angle = 20°

We need to calculate the speed of the two objects after the collision if they remain stuck together

Using conservation of momentum

$m_{1}v_{1}+m_{2}v_{2}=Mv$

Put the value into the formula

On x axis,

$6\times8.6+17\times11\cos20=23v\cos\theta$ ...(I)

On y axis,

$0+17\times11\sin20=23v\sin\theta$ ....(II)

Squaring and addin equation (I) and (II)

$v=\dfrac{(6\times8.6+17\times11\cos20)^2+(17\times11\sin20)^2}{23^2}$

$v=\sqrt{105.41}\ m/s$

$v=10.26\ m/s$

Hence, The speed of the two objects after the collision if they remain stuck together is 10.26 m/s.

0,0(0 оценок)