Physics: A particle with mass 1.53 kg oscillates horizontally at the end of a horizontal spring. A student measures an amplitude of 0.987 m and a duration of 121 s for 78 cycles of oscillation. Find the frequency (f), the speed at the equilibrium position (vmax), the spring constant (k), the potential energy at an endpoint (Umax), the potential energy when the particle is located 60.5% of the amplitude away from the equiliibrium position (U), and the kinetic energy (K), and the speed (v), at the same position.

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A particle with mass 1.53 kg oscillates horizontally

genyjoannerubiera

14.05.2020

0.645 Hz

38.959 N/m

4.981 m/s

18.976 J

6.495 J

12.031 J

3.965 m/s

Explanation:

k = Spring constant

m = Mass = 1.53 kg

A = Amplitude = 0.987 m

Number of cycles = 78

Time = 121 s

Frequency is given by

The frequency is 0.645 Hz

We have the relation

Spring constant is 38.959 N/m

Energy is conserved

The speed is 4.981 m/s

Potential energy is given by

The energy is 18.976 J

At 60.5%

The energy is 6.495 J

Total energy

The energy is 12.031 J

Speed

The speed is 3.965 m/s

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