fonsworth5
15.07.2020 •
Physics
A point charge of -4.28 pC is fixed on the y-axis, 2.79 mm from the origin. What is the electric field produced by this charge at point P, which is on the x-axis, 9.83 mm from the origin
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Ответ:
E = (-3.61^i+1.02^j) N/C
magnitude E = 3.75N/C
Explanation:
In order to calculate the electric field at the point P, you use the following formula, which takes into account the components of the electric field vector:
(1)
Where the minus sign means that the electric field point to the charge.
k: Coulomb's constant = 8.98*10^9Nm^2/C^2
q = -4.28 pC = -4.28*10^-12C
r: distance to the charge from the point P
The point P is at the point (0,9.83mm)
θ: angle between the electric field vector and the x-axis
The angle is calculated as follow:
The distance r is:
You replace the values of all parameters in the equation (1):
The electric field is E = (-3.61^i+1.02^j) N/C with a a magnitude of 3.75N/C
Ответ:
The surface area of a sphere can be found using the formula SA=4(x)pi(x)R squared. Middleton Middle School wants to paint kickballs purple for their carnival. The kickballs are all the same size. They used 6923.7 inches
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x=times
Explanation: