A point charge with charge q1 = 4.00 μC is held stationary at the origin. A second point charge with charge q2 = -4.20 μC moves from the point ( 0.135 m , 0) to the point ( 0.250 m , 0.250 m ). How much work W is done by the electric force on the moving point charge? Express your answer in joules. Use k = 8.99×109 N⋅m2/C2 for Coulomb's constant: k=14πϵ0. View Available Hint(s)

The value is

Explanation:

From the question we are told that

    The first charge is  

   The second  charge is  

    The position of the first charge is  

    The initial position of the second charge is  

    The final  position of the second charge is  

Generally the  electric potential  energy of the second charge at initial position is mathematically represented as

Here  

So

=>    

Generally the  electric potential  energy of the second charge at initial position is mathematically represented as

Here  

 =>  

So

=>    

Generally the workdone is mathematically represented as

=>  

=>        

4.23 beats / seconds

Explanation:

Frequency heard = f = f₁ - f₂

f₂ = f₁  √ ( F₂ / F₁)

f = f₁ - f₁ √ ( F₂ / F₁) = f₁ ( 1 - √ ( F₂ / F₁) = 523 Hz ( 1 - 0.9919 ) = 4.23 beats / seconds