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daskatingpanda
15.04.2020 •
Physics
A potential difference of 35 mV is developed across the ends of a 12.0-cm-long wire as it moves through a 0.27 T uniform magnetic field at a speed of 6.0 m/s. The magnetic field is perpendicular to the axis of the wire. What is the angle between the magnetic field and the wire's velocity?
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Ответ:
Angle between magnetic field and wire velocity is![10.372^{\circ}](/tpl/images/0602/0879/c5540.png)
Explanation:
We have given potential difference e = 35 mV = 0.035 volt
Length of the wire l = 12 cm = 0.12 m
Velocity v = 6 m/sec
Magnetic field B = 0.27 T
It is known that potential difference developed
So angle between magnetic field and wire velocity is![10.372^{\circ}](/tpl/images/0602/0879/c5540.png)
Ответ:
simplifying this expression (√8^4 × √6^4)^3/2 = 110592
so 2^12 ×3^3= 110592
similar 2^9 ×6^3 =110592