"A power of 200 kW is delivered by power lines with 48,000 V difference between them. Calculate the current, in amps, in these lines."

9.6×10⁹ A

Explanation:

From the question above,

P = VI Equation 1

Where P = Electric power, V = Voltage, I = current.

make I the subject of the equation

I = P/V Equation 2

Given: P = 200 kW = 200×10³ W, V = 48000 V.

Substitute these vales into equation 2

I = 200×10³×48000

I = 9.6×10⁹ A.

Hence the current in the line is 9.6×10⁹ A.

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Explanation: