A roller coaster starts at a point 30 m above the bottom of a dip with a speed of 25 m/s. Neglect friction, what will be the speed of the rollercoaster at the top of the next slope, which is 45 m above the bottom of the dip

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Ответ:

ashiteru123

15.04.2020

Physics

$48\times 10^6\ Pa,\ 2.083\times 10^{-8}\ Pa^{-1}$

Explanation:

Given

Initial volume is $V_1=600\ cm^3$

Pressure increase $P=3.6\times 10^6\ Pa$

Volume decrease $\Delta V=-0.45\ cm^3$

Bulk modulus is given by

$\Rightarrow k=-V\dfrac{dP}{dV}$

Insert the values

$\Rightarrow k=-600\times \dfrac{3.6\times 10^6}{-0.45}\\\\\Rightarrow k=48\times 10^6\ Pa$

Compressibility is the inverse of bulk modulus

$\therefore \text{Compressibility= }\dfrac{1}{k}\\\\\Rightarrow \dfrac{1}{48\times 10^6}=2.083\times 10^{-8}\ Pa^{-1}$

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