Physics: A Semi truck(m=20,000kg) is 10 m from a car(m=200kg). What is the force of gravity between them(G=6.67*10^-11N•m^2/kg^2)

A Semi truck(m=20,000kg) is 10 m from a car(m=200kg). - id20000102005155507, haleymoodie6034

anggar20

18.01.2022

F = 2.668*10_-6[N]

Explanation:

We can calculate this force using the law of universal gravitation raised by Isaac Newton

$m_{t}=20000[kg]\\m_{c}= 200[kg]\\r = 10[m]\\G = 6.67*10^{-11}[\frac{N*m^{2} }{kg} ] \\$

And the force is given by the following expression:

$F=G*\frac{m_{t}*m_{c}}{r^{2} } \\F=6.67*10^{-11} *\frac{20000*200}{10^{2} }\\F=2.668*10^{-6} [N]$

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JakerGamer

09.06.2023

Explanation:

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