Physics: A small block of wood is thrown inside a container filled with water. If only half of the wood is submerged in water and displayes 2 litre of water in the container. What is the weight of the wood

A small block of wood is thrown inside a container

MarsBars8798

23.01.2021

$\Delta V=1.667\times10^{-3}$

Explanation:

Given the initial temperature T_i=2° C

final temperature T_f= 32° C

The original volume of water Vo=268.8 mL= 0.2688 L

we need to calculate the change in the volume

As we know that volume expansion is given by

$\frac{\Delta V}{V_0}= \beta\Delta T$

ΔV= change in Volume

β= expansion coefficient = $207\times10^{-6} K^{-1}$

therefore,

$\Delta V= \beta\Delta T V_0$

plugging values we get

$\Delta V=207\times10^{-6} K^{-1} (32-2)\times0.2688$

$\Delta V=1.667\times10^{-3}$

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