a tennis ball is launched from the floor at a velocity of 90 m/a at an angle of 13 degrees to the horizontal. calculate its range

~186

Explanation:

1) R= (V^2 × sin A ) /g

V=90 m/a

A= 13°

g= 9.8 or 10 (I will take 9.8 for right result)

R= (90^2 × sin 13) / 9.8 = 185.928932672 ~ 186

We first calculate the work effectively done by the force when it compressed the steel cylinder. This is solved by multiplying the distance that the cylinder was compressed by and its causing force.
0.010 m * 13,000 N = 130 N-m

Then, we solve for the work done by the 1,500 N force:
0.10 m * 1,500 N = 150 N-m

We then take the ratio of the efficient:experimental
130 N-m / 150 N-m = 0.87 = 87%