hannahelisabeth19
01.11.2020 •
Physics
A tractor drags a 313kg plow across a field at 2.0 m/s . If the coefficient of friction between the plow and the ground is 0.570, how much force does the tractor apply to the plow ?
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Ответ:
The tractor applies 1,748.418 N to the plow.
Explanation:
Net Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn=m.a
If the acceleration is zero, then the net force is also zero. That means all forces acting on the mass are balanced.
The tractor drags the m=313 Kg plow at a constant speed, thus the acceleration is zero and so is the net force.
The horizontal forces acting on the plow are:
The force applied by the tractor FtThe friction of the ground FrSince both forces are balanced, then:
Ft=Fr
The friction force is calculated as:
Where
is the coefficient of friction between the plow and the ground and N is the normal force. In the situation described, the normal force is equal to the weight of the plow:
The normal force is N=3,067.4 N
The friction force is now calculated:
Thus, the tractor applies 1,748.418 N to the plow.
Ответ:
Sound vision system. Parametric sonar system. Pulsed acoustics for pollution monitoring. Matched field processing activities
Explanation: