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manlyman31
02.02.2022 •
Physics
A train car with mass of 2000 kg is moving at 10 m/s. The train needs to stop in 5 seconds. What average force is required for this to happen
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Ответ:
a) 4.844 m/s
b) FRACTION OF LOST 1.058
Explanation:
Let 0.2 kg puck be 1 and
0.3kg puck be 2
Puck 1 is moving along x while 2 is at rest
from conservation of momentum
Along x
m1 =0.2 kg
m2 = 0.3 kg
u2 = 0
u1 = 9.1
solving for V2
Along y
Solving for Vy2
Vy2 = -2.928 m/s
Therefore,
V(final velocity of puck 2)![= \sqrt{3.86^2 + (-2.928)^2} = 4.844 m/s](/tpl/images/0395/7802/9f486.png)
b) Kinetic energy lost= initial KE - Final KE
=![[(1/2) \times (0.2) \times (9.1)^2 + 0] - [(1/2) \times (0.2) \times (5.5)^2 +(1/2) \times (0.3) \times (4.844)^2]](/tpl/images/0395/7802/169cd.png)
= 8.281 - (3.025 +3.51)
= 8.766 J
FRACTION OF LOST![= \frac{8.766}{8.281} = 1.058](/tpl/images/0395/7802/75a4d.png)