A uniform electric field of strength E points to the right. An electron is fired with a velocity v0 to the right and travels a distance d before coming to a stop. An second electron is then fired upwards through the same field at a velocity of v0. After the electron moving vertical has traveled vertically upwards a distance d, how far will it have moved horizontally?

Explanation:

From the question we are told that:

The Electric field of strength direction =Right

The Velocity of The First Electron=V_0

The Velocity of The Second Electron=V_0

Therefore

Generally, the equation for the Horizontal Displacement of electron is mathematically given by

Where

Acceleration is given as

And

Time

Therefore horizontal displacement towards the left is

4748.4

Explanation:

The first number after the decimal is the tenths place and when it says round it means look at the number after it and if it's above four then raise the tenths place by one.