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epicriderexe
27.12.2019 •
Physics
A0.140 kg baseball is thrown horizontally with a velocity of 28.9 m/s. it is struck with a constant horizontal force that lasts for 1.85 ms, which results in a velocity of 37.0 m/s in the opposite direction. what was the magnitude of the horizontal force? a. 0.613 knb. 0.613 kn c. 2.19 kn d. 2.80 kn
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Ответ:
To solve this problem, we will express the Force according to Newton's second Law, and acceleration, such as the change of velocity in the body by a certain distance, therefore,
The magnitude of the force is given as
F = ma
Where,
m = mass
a = Acceleration
That can be expressed as,
Replacing with our values we have
F = 0.140kg * (\frac{37+28.9}{1.85*10^{-3}})
F = 4987.03N
F= 4.9kN
Therefore the magnitude of the horizontal force is 4.9kN
Ответ:
answer is b. any movement that uses your muscles and requires energy
Explanation: